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10道一元二次解方程?

59

x² - 5x - 176 = 0

解:使用求根公式,$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$a = 1, b = -5, c = -176$

$\Delta = (-5)^2 - 4 \cdot 1 \cdot (-176) = 25 + 704 = 729$

$x = \frac{5 \pm \sqrt{729}}{2} = \frac{5 \pm 27}{2}$

$x_1 = 16, x_2 = -11$

x² - 26x + 133 = 0

解:使用求根公式

$a = 1, b = -26, c = 133$

$\Delta = (-26)^2 - 4 \cdot 1 \cdot 133 = 676 - 532 = 144$

$x = \frac{26 \pm \sqrt{144}}{2} = \frac{26 \pm 12}{2}$

$x_1 = 19, x_2 = 7$

x² + 10x - 11 = 0

解:使用求根公式

$a = 1, b = 10, c = -11$

$\Delta = 10^2 - 4 \cdot 1 \cdot (-11) = 100 + 44 = 144$

$x = \frac{-10 \pm \sqrt{144}}{2} = \frac{-10 \pm 12}{2}$

$x_1 = 1, x_2 = -11$

x² - 3x - 304 = 0

解:使用求根公式

$a = 1, b = -3, c = -304$

$\Delta = (-3)^2 - 4 \cdot 1 \cdot (-304) = 9 + 1216 = 1225$

$x = \frac{3 \pm \sqrt{1225}}{2} = \frac{3 \pm 35}{2}$

$x_1 = 19, x_2 = -16$

x² + 13x - 140 = 0

解:使用求根公式

$a = 1, b = 13, c = -140$

$\Delta = 13^2 - 4 \cdot 1 \cdot (-140) = 169 + 560 = 729$

$x = \frac{-13 \pm \sqrt{729}}{2} = \frac{-13 \pm 27}{2}$

$x_1 = 7, x_2 = -20$

x² + 13x - 48 = 0

解:使用求根公式

$a = 1, b = 13, c = -48$

$\Delta = 13^2 - 4 \cdot 1 \cdot (-48) = 169 + 192 = 361$

$x = \frac{-13 \pm \sqrt{361}}{2} = \frac{-13 \pm 19}{2}$

$x_1 = 3, x_2 = -16$

x² + 5x - 176 = 0

解:使用求根公式

$a = 1, b = 5, c = -176$

$\Delta = 5^2 - 4 \cdot 1 \cdot (-176) = 25 + 704 = 729$

$x = \frac{-5 \pm \sqrt{729}}{2} = \frac{-